2023-05-08 分类 技术 标签 python django 阅读 217
当页面中form使用POST方式向后台提交时,报如下错误:
禁止访问 (403) CSRF验证失败. 请求被中断. Help Reason given for failure: CSRF token missing or incorrect. In general, this can occur when there is a genuine Cross Site Request Forgery, or when Django's CSRF mechanism has not been used correctly. For POST forms, you need to ensure: Your browser is accepting cookies. The view function passes a request to the template's render method. In the template, there is a {% csrf_token %} template tag inside each POST form that targets an internal URL. If you are not using CsrfViewMiddleware, then you must use csrf_protect on any views that use the csrf_token template tag, as well as those that accept the POST data. The form has a valid CSRF token. After logging in in another browser tab or hitting the back button after a login, you may need to reload the page with the form, because the token is rotated after a login. You're seeing the help section of this page because you have DEBUG = True in your Django settings file. Change that to False, and only the initial error message will be displayed. You can customize this page using the CSRF_FAILURE_VIEW setting.
在网上查找了很多资料,普遍采用的解决方法是:
检查settings.py中是否有下面的配置,如没有加上: MIDDLEWARE_CLASSES = ( 'django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.middleware.csrf.CsrfViewMiddleware', # 确认存在 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.contrib.messages.middleware.MessageMiddleware', 'django.middleware.clickjacking.XFrameOptionsMiddleware', ) html中的form添加模板标签{% csrf_token %} <form action="/saveBlog/" method="post"> {% csrf_token %} ... </form> 针对views.py进行修改 from django.shortcuts import render_to_response from django.template import RequestContext def some_blog(request): # ... return render_to_response('my_template.html', my_data_dictionary, context_instance=RequestContext(request)) 以上各步都基本照做了。其中针对视图的修改,因我的写法与网上不一样,我的是: def edit_blog(request): template = get_template('editBlog.html') moods = Mood.objects.all() html = template.render(locals()) `` return HttpResponse(html) 因为官方文档上说render是render_to_response的shortcut,所以没有照网站资料上说的去改。于是错误总是无法解决。
几番挣扎之后,终于在Django出错页面中自己给出的解决办法中有一条:The view function passes a request to the template's rendermethod.(即:视图函数中传递 request 给模板的render方法)。
按这个访求修改后,终于解决问题了!! def edit_blog(request): template = get_template('editBlog.html') moods = Mood.objects.all() html = template.render(locals(), request) # 把request传递给template.render() `` return HttpResponse(html)